mysql查询当天的所有信息: 代码如下 select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())
这个有一些繁琐,还有简单的写法: 代码如下 select * from table where date(regdate) = curdate();
另一种写法没测试过 查询当天的记录 代码如下 select * from hb_article_view where TO_DAYS(hb_AddTime) = TO_DAYS(NOW())
date()函数获取日期部分, 扔掉时间部分,然后与当前日期比较即可
代码如下 SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now()); 查询上周的数据 代码如下 SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;
查询当前月份的数据 查询距离当前现在6个月的数据 代码如下 select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now(); 查询上个月的数据 代码如下 select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m') select * from `user` where DATE_FORMAT(pudate,'%Y%m') = DATE_FORMAT(CURDATE(),'%Y%m') ; select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())
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代码如下
SELECT count( * ) AS c, sum( if( logusertype =2, logusertype, 0 ) ) /2 AS a, sum( if( logusertype =3, logusertype, 0 ) ) /3 AS b 查询30秒内记录的总数,loguser等于2的记录的总数和,和 loguser等于3的记录的总数. if( logusertype =2, logusertype, 0 ) 如果logusetype等于2 就在logusertype上累加,否则加0。 sum( if( logusertype =2, logusertype, 0 ) ) 把logusertype都累加起来。 sum( if( logusertype =2, logusertype, 0 ) ) /2 AS a, 除以2是统计个数。 UNIX_TIMESTAMP(NOW())计算当前时间的秒数, UNIX_TIMESTAMP( logendtime )计算logendtime的秒数 |